If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3z^2+10z-25=0
a = 3; b = 10; c = -25;
Δ = b2-4ac
Δ = 102-4·3·(-25)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-20}{2*3}=\frac{-30}{6} =-5 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+20}{2*3}=\frac{10}{6} =1+2/3 $
| 43+11x=4 | | 2/9x+5=7 | | -2(x+2)-x-5=-3(x+7)+12 | | -4(6+n)+3=28 | | 6(-3x-2)=-156 | | 15x+20=162.50 | | 2x+18=-33+5 | | 40+5y-4=16y-13-4y | | 40+5y-4=16y-1-4y | | 5(3-c/7)=3 | | 5(3-(c/7))=8 | | 4x(3-1)=2x+12 | | -x+3-5x=-6x-9 | | x+(x*0.10)=100 | | -3z+8+-2z=72 | | -15x(-6)=65/(-7)= | | (3x-5)/2+(8x-12)/7=9 | | -3(1-n)-4=-14-4n | | (3y+1)^5=0 | | -16x^2+800x=0 | | 7w^2=14w | | 6(8g+3)+45=153 | | 3x-9/4=-3 | | 4x-5x+2=3(2x-4) | | 23-3x=33 | | -1.4+x/2.5=-6.32 | | 1/6(6x-8)-2=39 | | A(t)=25000(1.04) | | 10-3b=13 | | 3x+13x-1=4(4x+2) | | 8+x-4x=-19 | | -5.4x+40=360 |